VBScript InStrRev Function

Returns the position of an occurrence of one string within another, from the end of string.

Syntax: VBScript InStrRev Function

InStrRev(string1, string2[, start[, compare]])

Arguments: VBScript InStrRev Function

string1

The string expression being searched. Required.

string2

The string expression being searched for. Required.

start

The numeric expression that sets the starting position for each search. If omitted, -1 is used, which means that the search begins at the last character position. If start contains Null, an error occurs. Optional.

compare

The numeric value indicating the kind of comparison to use when evaluating substrings. If omitted, a binary comparison is performed. See Settings section for values. Optional.

Settings: VBScript InStrRev Function

The compare argument can have the following values:

Constant	Value	Description
vbBinaryCompare	0	Perform a binary comparison.
vbTextCompare	1	Perform a textual comparison.

Return Values: VBScript InStrRev Function

InStrRev returns the following values:

If	InStrRev returns
string1 is zero-length	0
string1 is Null	Null
string2 is zero-length	Start
string2 is Null	Null
string2 is not found	0
string2 is found within string1	Position at which match is found
start > Len(string2)	0

Remarks: VBScript InStrRev Function

Note that the syntax for the InStrRev function is not the same as the syntax for the InStr function.

The following examples use the InStrRev function to search a string:

Dim SearchString, SearchChar, MyPos

SearchString ="XXpXXpXXPXXP" ' String to search in.

SearchChar = "P" ' Search for "P".

MyPos = InstrRev(SearchString, SearchChar, 10, 0) ' A binary comparison starting at position 10. Returns 9.

MyPos = InstrRev(SearchString, SearchChar, -1, 1) ' A textual comparison starting at the last position. Returns 12.

MyPos = InstrRev(SearchString, SearchChar, 8) ' Comparison is binary by default (last argument is omitted). Returns 0.