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Returns a string in which a specified substring has been replaced with another substring a specified number of times.
Replace(expression, find, replacewith[, start[, count[, compare]]])
expression
A string expression containing substring to replace. Required.
find
The substring being searched for. Required.
replacewith
The replacement substring. Required.
start
The position within expression where substring search is to begin. If omitted, 1 is assumed. Optional.
count
The number of substring substitutions to perform. If omitted, the default value is -1, which means make all possible substitutions. Optional.
compare
The numeric value indicating the kind of comparison to use when evaluating substrings. See Settings section for values. Optional.
The compare argument can have the following values:
Constant |
Value |
Description |
vbBinaryCompare |
0 |
Perform a binary comparison. |
vbTextCompare |
1 |
Perform a textual comparison. |
Replace returns the following values:
If |
Replace returns |
expression is zero-length |
Zero-length string (""). |
expression is Null |
An error. |
find is zero-length |
Copy of expression. |
replacewith is zero-length |
Copy of expression with all occurrences of find removed. |
start > Len(expression) |
Zero-length string. |
count is 0 |
Copy of expression. |
The return value of the Replace function is a string, with substitutions made, that begins at the position specified by start and concludes at the end of the expression string. It is not a copy of the original string from start to finish.
The following example uses the Replace function to return a string:
Dim MyString
MyString = Replace("XXpXXPXXp", "p", "Y") ' A binary comparison starting at the beginning of the string. Returns "XXYXXPXXY".
MyString = Replace("XXpXXPXXp", "p", "Y", ' A textual comparison starting at position 3. Returns "YXXYXXY". 3, -1, 1)
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